Find the sum of the intercepts cut off by the plane `2x+yz=5` , on the coordinate axes.

Explanation

Equation of plane,

`2x+y-z = 5`

Equation of plane in intercept form,

`(2x)/5+y/5-z/5 = 1`

`=>x/(5/2)+y/5+z/(-5) = 1`

Comparing the above equation with the standard intercept form,

`x/a+y/c+z/c = 1`

We get the intercepts as, `a = 5/2, b = 5, c = -5`

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