The simple harmonic vibrations of two particles are `y_(1)= 5sin (100t) and y_(2) = 4 cos (100t + pi/4)`. The phase difference between both particles is

The displacements of two linear simple harmonic oscillators are given by x_(1)=3 "sin" (100 t+ theta) " and " x_(2)=4 "cos" (100 t) . What is the phase difference between the velocities of these oscillators ?

Two simple harmonic motions are represented by y_(1)= 10 "sin" omega t " and " y_(2) =15 "cos" omega t . The phase difference between them is

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

Two simple harmonic motion are represented by equations y_(1) = 4 sin (10 t + phi) rArr y_(2) = 5 cos 10t What is the phase difference between their velocities ?

Two simple harmonic motions are given by y_(1) = a sin [((pi)/(2))t + phi] and y_(2) = b sin [((2pi)/( 3))t + phi] . The phase difference between these after 1 s is

Two simple harmonic motions are given by y_(1) = a sin [((pi)/(2))t + phi] and y_(2) = b sin [((2pi)/( 3))t + phi] . The phase difference between these after 1 s is

Two simple harmonic motions are given by y_(1) = a sin [((pi)/(2))t + phi] and y_(2) = b sin [((2pi)/( 3))t + phi] . The phase difference between these after 1 s is

The displacement of two particles executing S.H.M are represented by y_(1) = a sin(wt + phi) and y_(2) = a cos w t . The phase difference between the velocities of these particles is

Two simple harmonic are represented by the equation y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit . The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.

Two simple harmonic are represented by the equation y_(1)=0.1 sin (100pi+(pi)/3) and y_(2)=0.1 cos pit . The phase difference of the velocity of particle 1 with respect to the velocity of particle 2 is.