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x-1=8(x-1)/(3)+(y+1)/(2)-9...

x-1=8(x-1)/(3)+(y+1)/(2)-9

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(x+1)/(2)+(y-1)/(3)=8;(x-1)/(3)+(y+1)/(2)=9

(x+1)/(2)+(y+1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 then x=………

Solve for x and y : (x+1)/(2)+(y-1)/(3)=9, (x-1)/(3)+(y+1)/(2)=8 .

(x+1)/(2)+(y-1)/(3)=9,(x-1)/(3)+(y+1)/(2)=8 In the above problem y= ……….

Solve the following equations: (x+1)/(2)+(y-1)/(3)=8" and "(x-1)/(3)+(y+1)/(2)=9

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

Solve by the elimination method: (x+1)/(2)+(y-1)/(3)=9 and (x+1)/(3)+(y-1)/(2)=8

(4)/(x)+(3)/(y)=1,(8)/(x)-(9)/(y)=7

(1)/(2) + (1)/(4) + (1)/(8) + (1)/(16) + ….. = x , (1)/(3) + (1)/(9) + (1)/(27) + (1)/(81) + … = y, then