Passage XI) The differential equation of a particle undergoing SHM is given by `a(d^(2)x)/(dt^(2))`+bx = 0. The particle starts from the extreme position.
The time period of osciallation is given by

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

Passage XI) The differential equation of a particle undergoing SHM is given by a(d^(2)x)/(dt^(2)) +bx = 0. The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is

The differential equation of a particle undergoing SHM is given by a a(d^(2)"x")/(dt^(2))+b"x"=0 ltbr.gt The particle starts from the extreme position The equation of motion may be given by :

The differential equation of a particle undergoing SHM is given by a a(d^(2)"x")/(dt^(2))+b"x"=0 . The particle starts from the extreme position. The ratio of the maximum acceleration to the maximum velocity of the particle is –

The differential equation of a particle performing a S.H.M. is (d^(2)x)/(dt^(2))+ 64x=0 . The period of oscillation of the particle is

The equation of SHM of a particle is given as 2(d^(2)x)/(dt^(2))+32x=0 where x is the displacement from the mean position. The period of its oscillation ( in seconds) is -

If the particle in linear S.H.M. starts from the extreme left position, then its equation of motion is given by

If the particle in linear S.H.M. starts from the extreme left position, then its equation of motion is given by

Differential equation for a particle performing linear SHM is given by (d^(2)x)/(dt^(2))+3xx=0 , where x is the displacement of the particle. The frequency of oscillatory motion is

The equation of motion of a particle executing SHM is ((d^2 x)/(dt^2))+kx=0 . The time period of the particle will be :