[" In the adjoining figure the impedance of the circuit will be "],[qquad 90vv sqrt(theta)quad (1)/(2)quad (x_(0))/(2)=20Omega]

In the adjoining figure the impedence of the circuit will be

In the circuit of adjoining figure the current through 12 Omega resister will be

In the circuit of adjoining figure the current through 12 Omega resister will be

In the circuit of adjoining figure the current through 12 Omega resistor will be

In the figure shown, a current of 2 amperes flows in the circuit. The impedence of the circuit is-

In the figure shown, a current of 2 amperes flows in the circuit. The impedence of the circuit is-

A series AC circuit has a resistance of 4omega and an inductor of reactance 3omega . The impedance of the circuit is z_1 . Now a capacitor of reactance 6omega is connected in the series of above combination, the impedance becomes z_(2) , Then (z_(1))/(z_(2)) will be-

An LCR circuit contains R=50 Omega, L=1 mH and C=0.1 muF . The impedence of the circuit will be minimum for a frequency of

An LCR circuit contains R=50 Omega, L=1 mH and C=0.1 muF . The impedence of the circuit will be minimum for a frequency of