If the power of `(1,-2)` with respect to the circle `x^2 +y^2=1` is radius and (3,2) is centre of a circle, then equation is

The power of (1,1) with respect to the circle x^(2)+y^(2)-4x+3y+k=0 is 3, then k

The power of (1,1) with respect to the circle x^(2)+y^(2)-4x+3y+k=0 is 3 then k is

The power of (1,1) with respect to the circle x^(2)+y^(2)-4x+3y+k=0 is 3, then k

If (1,-3) is the centre of the circle x^(2) + y^(2) +ax + by + 9 =0 its radius is

Equation of a circle with centre (4, 3) touching the circle x^2+y^2=1 is

In the figure, O is the centre of the circle and x^2+y^2=25 is the equation of the circle. Write the equation of the circle whose centre is at the origin and radius is 3. .

The equation of the circle with centre (3, -2) and radius 3 is

If one of the diameters of the circle x^2+ y^2-2x-6y + 6=0 is a chord to the circle with centre (2, 1), then the radius of the circles is :

If one of the diameters of the circle x^2+y^2-2x-6y+ 6 = 0 is a chord to the circle with centre (2, 1), then the radius of circle is: