`tan (pi/24) tan ((3pi)/24 )tan ((5pi)/24) tan((7pi)/24) tan ((9pi)/24) tan ((11pi)/24) tan ((16pi)/24)`

tan((pi)/(24))tan((3 pi)/(24))tan((5 pi)/(24))tan((7 pi)/(24))tan((9 pi)/ (24))tan((11 pi)/(24))tan((16 pi)/(24))

Prove: (ii) tan ((pi)/12) tan ((5 pi)/12) tan ((7 pi)/12) tan ((11 pi)/12) = 1

Evaluate tan ((pi)/20).tan((3pi)/20).tan((5pi)/20).tan((7pi)/20).tan((9pi)/20 )

tan((pi)/(20))tan(3(pi)/(20))tan(5(pi)/(20))tan(7(pi)/(20))tan(9(pi)/ (20))

Prove that tan (pi/12)tan((5pi)/12)tan ((7pi)/12)tan((11pi)/12)=1

(tan(pi/4)+tan(pi/6))/(1-tan(pi/4)tan(pi/6))=?

The value of (1+tan\ (3pi)/8*tan\ pi/8)+(1+tan\ (5pi)/8*tan\ (3pi)/8)+(1+tan\ (7pi)/8*tan\ (5pi)/8)+(1+tan\ (9pi)/8* tan\ (7pi)/8)

tan. (pi)/(10) + tan. (3pi)/(10) + tan. (7pi)/(10) + tan. (9pi)/(10) =

tan((pi)/(10))+tan((3 pi)/(10))+tan((7 pi)/(10))+tan((9 pi)/(10))=

Prove that tan((pi)/(12))+tan((pi)/(6))+tan((pi)/(12))tan((pi)/(6))=1