The solution of the inequality `2x -1 <= x^2 + 3<=x-1` is

The solution to the inequality |2x-1| lt 6 is

If the solution of the inequality (x^(2)-x-1)(x^(2)-x-7)<-5 is x in(alpha,beta)uu(gamma,delta) then find the value of alpha+beta+gamma+delta

The solution set of the inequality 2(4x-1)le3(x+4) is

The solution set of the inequality (1)/(x-2)-(1)/(x)<=(2)/(x+2) is (-alpha,beta]uu(gamma,alpha)uu[delta,oo), then

Find the solution of the inequality 2log_(1/4)(x+5)>9/4log_(1/(3sqrt(3)))(9)+log_(sqrt(x+5))(2)

Find the solution of the inequality 2log_(1/4)(x+5)>9/4log_(1/(3sqrt(3)))(9)+log_(sqrt(x+5))(2)

The solution set of the inequality max {1-x^2,|x - 1|}<1 then

The solution of the inequality log_(x)(4x^(2)-1)<2, is

If the solution set of |x-k|<2 is a subset of the solution set of the inequality (2x-1)/(x+2)<1 then the number of possible integral value(s) of 'k' is/are-