A buffer solution of `0.080M Na_(2)HPO_(4)` and `0.020 M Na_(3)PO_(4)` is prepared. The electrolytic oxidation of `1.0 mmol RNHOH` is carried out in `100mL` buffer to give
`RNHOH + H_(2)O rarr RNO_(2) + 4H^(o+) + 4e^(-)`
Calculate approximate `pH` of the solution after oxidation is complete `pK_(a_(2)), pK_(a_(2))`, and `pK_(a_(3))` of `H_(3)PO_(4)` are `2.12,7.20`, and `12.0`, respectively.

A buffer solution 0.04 M in Na_(2)HPO_(4) and 0.02 in Na_(3)PO_(4) is prepared. The electrolytic oxidation of 1.0 milli-mole of the organic compound RNHOH is carried out in 100 mL of the buffer. The reaction is RNHOH+H_(2)OrarrRNO_(2)+4H^(+)+4e^(-) The approximate pH of solution after the oxidation is complete is : [Given : for H_(3)PO_(4),pK_(a1)=2.2,pK_(a2)=7.20,pK_(a3)=12]

A buffer solution 0.04 M in Na_(2)HPO_(4) and 0.02 in Na_(3)PO_(4) is prepared. The electrolytic oxidation of 1.0 milli-mole of the organic compound RNHOH is carried out in 100 mL of the buffer. The reaction is RNHOH+H_(2)OrarrRNO_(2)+4H^(+)+4e^(-) The approximate pH of solution after the oxidation is complete is : [Given : for H_(3)PO_(4),pK_(a1)=2.2,pK_(a2)=7.20,pK_(a3)=12] (a) 6.90 (b) 7.20 (c) 7.5 (d)None of these

A buffer solution 0.04 M in Na_2HPO_4 and 0.02 M in Na_3 PO_4 is prepared. The electrolytic oxidation of 1.0 milli -mole of the organic compound RNHOH is carried out in 100 mL of the buffer. The reaction is RNHOH +H_2O to RNO_2 +4H ^(+) + 4e ^(-) The approximate pH of solution after the oxidation is complete is: [Given : for H_3O PO_4, pK_(a_1) =7.20 , pK_(a_2) =12]

pK_(a1) , pK_(a_(2)) and pK_(a_(3)) of H_(3)PO_(4) are respectively x,y and z. pH of 0.1 M Na_(2)HPO_(4) solution is

The pH of a buffer solution of 0.1 M NH_(4)OH [ pK_(a)=4.0] and 0.1 M NH_(4)Cl is

The pH of the resultant solution of 20 mL of 0.1 M H_(3)PO_(4) and 20 mL of 0.1 M Na_(3)PO_(4) is :

The pH of the resultant solution of 20 mL of 0.1 M H_(3)PO_(4) and 20 mL of 0.1 M Na_(3)PO_(4) is :