A thin lens made of a material of refractive index `mu_(0)` has a focal length `f_(0)` in air. Find the focal length of this lens if it is immersed in a liquid of refractive index `mu`.

A glass convex lens of refractive index 3/2 has got a focal length equal to 0.3 m. Find the focal length of the lens if it is immersed in water of refractive index 4//3 .

A biconvex lens of refractive index "1.5" has a focal length of "20cm" in air.Its focal length when immersed in a liquid of refractive index "1.6" will be:

A double convex thin lens made of glass of refractive index 1.6 has radii of curvature 15 cm each. The focal length of this lens when immersed in a liquid of refractive index 1.63 is :

A converging lens of refractive index 1.5 and of focal length 15 cm in air, has the same radii of curvature for both sides. If it is immersed in a liquid of refractive index 1.7 , find the focal length of the lens in the liquid.

A converging lens has a focal length of 20 cm in air. It is made of a material of refractive index 1.6. If it is immersed in a liquid of refractive index 1.3, what will be the new focal length? How does the nature of the lens change. If this lens is immersed is a liquid of refractive index 1.8 ?

A thin convex lens of refractive index 1.5cm has 20cm focal length in air. If the lens in completely immersed in a liquid of refractive index. 1.6, then its focal length will be

A thin convex lens of refractive index 1.5cm has 20cm focal length in air. If the lens in completely immersed in a liquid of refractive index. 1.6, then its focal length will be