(x)/(2)+(2y)/(3)=-1" 3) "x-(y)/(3)=3

Solve for x and y : (x)/(2)+(2y)/(3)=-1 x-(y)/(3)=3

(x)/(2)+(2y)/(3)=-1 And x-(y)/(3)

Solve for x and y: (x)/(2) + (2y)/(3)= -1 and x- (y)/(3)= 3

(x) / (2) + (y) / (3) = 1 (x) / (3) + (y) / (2) = 1

Find each of the following products: (i) (x - 4)(x - 4) (ii) (2x - 3y)(2x - 3y) (iii) ((3)/(4) x - (5)/(6) y) ((3)/(4)x - (5)/(6) y) (iv) (x - (3)/(x)) (x - (3)/(x)) (v) ((1)/(3) x^(2) - 9) ((1)/(3) x^(2) - 9) (vi) ((1)/(2) y^(2) - (1)/(3) y) ((1)/(2) y^(2) - (1)/(3) y)

If the join of (x_(1),y_(1)) and (x_(2),y_(2)) makes on obtuse angle at (x_(3),y_(3)), then prove than (x_(3)-x_(1))(x_(3)-x_(2))+(y_(3)-y_(1))(y_(3)-y_(2))<0

Solve:(1)/(2(2x+3y))+(12)/(7(3x-2y))=(1)/(2)(7)/(2x+3y)+(4)/(3x-2y)=2 where 2x+3y!=0 and 3x-2y!=0