`F - x` equation of a body of mass `2kg` in SHM is
`F + 8x = 0`
Here, `F` is in newton and `x` in meter.Find time period of oscillations.

F-x equation of a body in SHM is F + 4x=0 Here, F is in newton and x in meter. Mass of the body is 1 kg . Find time period of oscillations.

F-x equation of a body in SHM is F + 4x=0 Here, F is in newton and x in meter. Mass of the body is 1 kg . Find time period of oscillations.

a - x equation of a body in SHM is a + 16 x = 0 . Here, x is in cm and a in cm//s^(2) . Find time period of oscillations.

a - x equation of a body in SHM is a + 16 x = 0 . Here, x is in cm and a in cm//s^(2) . Find time period of oscillations.

a - x equation of a particle in SHM is a + 4x = 0 Here, a is in cm//s^(2) and x in cm.Find time period in second.

a - x equation of a particle in SHM is a + 4x = 0 Here, a is in cm//s^(2) and x in cm.Find time period in second.

Passage IX) For SHM to take place force acting on the body should be proportional to -x or F = -kx. If A be the amplitude then energy of oscillation is 1/2 k A^(2) Force acting on a block is F = ( − 4 x + 8 ) . Here F is in Newton and x the position of block on x-axis in meter If energy of osciallation is 18 J, between what points the block will oscillate?

For SHM to take place force acting on the body should be proportional to -x or F =- kx . If A be the amplitude then energy of oscillation is 1//2KA^(2) . Force acting on a block is F = (-4x +8) . Here F is in newton and x in the position of block on x-axis in meters

A force F=(10+0.50x) acts on a particle in the x direction, where F is in newton and x in meter. Find the work done by this force during a displacement form x=0 to x=2.0m