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An urn contains 3 white and 6 red balls....

An urn contains 3 white and 6 red balls. Four balls are drawn one by one with replacement from the urn. Find the probability  distribution of the number of red balls drawn. Also find mean and variance of the distribution.

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There are total 9 balls
Success:drawing a red ball.
`n=4,P=6/9=2/3,q=1/3`
P(r red balls)=P(X=r)
`=nC_rP^rQ^(n-r)=4C_r(2/3)^r(1/3)^(4-r)`
`=4C_r*2^r/3^4`
Mean=`sumx_iP_i`
`=0+8/81+(2*24)/81+(3*32)/81+(4*16)/81`
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