If `y=1/(t^2+t-2),w h e r et=1/(x-1),` then find the number of points where `f(x)` is discontinuous.

If y=1/(t^2+t-2),where \ t=1/(x-1), then find the number of points where f(x) is discontinuous.

If y=1/(t^2+t-2),where \ t=1/(x-1), then find the number of points where f(x) is discontinuous.

If y=(1)/(t^(2)+t-2), where t=(1)/(x-1), then find the number of points where f(x) is discontinuous.

If f(t) = 1/(t^(2)-t-6) and t = 1/(x-2) then the values of x which make the function f discontinuous are

The number of points where f(x) is discontinuous in [0,2] where f(x)={[cos pi x]:x 1}

If a function y=f(x) is defined as y=(1)/(t^(2)-t-6)and t=(1)/(x-2), t in R . Then f(x) is discontinuous at

If a function y=f(x) is defined as y=(1)/(t^(2)-t-6)and t=(1)/(x-2), t in R . Then f(x) is discontinuous at

Find the points of discontinuity of f(x)=(1)/(2sin x-1)

Let f(x)=(1-cosx)/(x^2),\ \ \ w h e n\ x!=0,\ f(x)=1,\ \ \ w h e n\ x=0 . Show that f(x) is discontinuous at x=0 .

Let f(x)={(1-cosx)/(x^2),\ \ \ w h e n\ x!=0 ; 1,\ \ \ \ w h e n\ x=0 . Show that f(x) is discontinuous at x=0 .