To increase the length of brass rod by `2%` its temperature should increase by `(alpha = 0.00002 "^(@)C^(-1))`

For what increase in temperature of a bras rod ,its length will increase by 0.5% alpha_("brass") = 0.00002^@C^(-1)

Solve the following problems : What will be the increase in length of a steel rod of length 0.5 m , when its temperature is increased by 60 ⁰C ? The coefficient of linear expansion of steel is 0.000013 ( 1/⁰C) .

How much should the temperature of a brass rod be increased so as to increase its length by 1% ? Given alpha for brass is 0.00002 .^(@)C^(-1) .

How much should the temperature of a brass rod be increased so as to increse its length by 1% ? Given alpha for brass is 0.00002 .^(@)C^(-1) .

The coefficient of linear expansion of a rod of length 1 m, at 27^@C , is varying with temperature as alpha = 2/T unit (300 K le T le 600 K) , where T is the temperature of rod in Kelvin. The increment in the length of rod if its temperature increases from 27^@C to 327^@C is

A copper rod of 88 cm and an aluminium rod of unknown length have their increase in length independent of increase in temperature. The length of aluminium rod is (alpha cu=1.7xx10^(-5) K^(-1) " and " alpha Al=2.2xx10^(-5) K^(-1))

A copper rod of 88 cm and an aluminium rod of unknown length have their increase in length independent of increase in temperature. The length of aluminium rod is (alpha cu=1.7xx10^(-5) K^(-1) " and " alpha Al=2.2xx10^(-5) K^(-1))