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If `A` is a square matrix such that `A^2=I` , then find the simplified value of `(A-I)^3+(A+I)^3-7Adot`

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Here, we are given, `A^2 = I`.
Now, `(A+I)^3 = (A+I)(A+I)(A+I)`
`= (A^2+IA+AI+I^2)(A+I)`
`=(I+A+A+I)(I+A)` (As `A^2 = I`)
`=(2I+2A)(I+A)`
`=2(I+A)(I+A)`
`=2(2(I+A)`
`=4I+4A`
...
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