Home
Class 13
CHEMISTRY
" For the indicator the ratio "([ln^(omi...

" For the indicator the ratio "([ln^(ominus)])/([HIn])" is "7.0" at "pH" of "4.3.K_(ln)" for the indicator will be: "

Promotional Banner

Similar Questions

Explore conceptually related problems

For the indicator 'HIn' the ratio (Ind^(Θ))//(HIn) is 7.0 at pH of 4.3 . What is K_(eq) for the indicator.

For the indicator 'Hin' the ratio (Ind^(Θ))//(HIn) is 7.0 at pH of 4.3 . What is K_(eq) for the indicator.

The rapid change of pH near the stoichiometric point of an acid base titration is the basis of indicator detectio. pH of the solution is related to ratio of the concentrations of the conjugate acid (Hin) and base (In^(-)) forms of the indicator given by the expression

The rapid change of pH near the stoichiometric point of an acid-base titration is the basic of indicator detection. pH of the solution is related to the ratio of the concentration of conjugate acid (Hin) and base (In^(-)) forms of the indicator by the expression

The rapid change of pH near the stoichiometric point of an acid-base titration is the basic of indicator detection. pH of the solution is related to the ratio of the concentration of conjugate acid (Hin) and base (In^(-)) forms of the indicator by the expression

The rapid change of pH near the stocichiometric point of an acid-base titration is the basis of indicator detrection. pH of the solution is related to the ratio of concentration of conjugate acid (HIn) to the concentration of base (In^(-)) froms of the indicator by the expression

The indicator constant for an acidic indicator, HIn is 5xx10^(-6)M . This indicator appears only in the colour of acidic form when ([In])/([HIn])le(1)/(20) and it appears only in the colour of basic form when ([HIn])/([In])le(1)/(40) . The pH range of indicator is [ Given : log 5=0.7]

The indicator constant for an acidic indicator, HIn is 5xx10^(-6)M . This indicator appears only in the colour of acidic form when ([In])/([HIn])le(1)/(20) and it appears only in the colour of basic form when ([HIn])/([In])le(1)/(40) . The pH range of indicator is [ Given : log 5=0.7]

In an acidic indicator HIn has an ionization constant is 10^(-8). The acid form of indicator is yellow and alkaline form is red. Which is correct statement? (Given : log2= 0.3, log3 = 0.48)