[" If 'p' is in equilibrium then "(T_(1))/(T_(2))" is "],[qquad [T_(1)],[30^(@)]]

If 'O' is at equilibrium then the values of the tension T_(1) and T_(2) are x, y, if 20 N is vertically down. Then x, y are

If 'O' is at equilibrium then the values of the tension T_(1) and T_(2) respectively.

The block is in equilibrium (i) T_(1)=(mgcosbeta)/(sin(alpha+beta))" "(ii)T_(2)=(mgcosalpha)/(sin(alpha+beta)) (iii)T_(1)/T_(2)=(cosbeta)/(cosalpha)" "(iv)T_(1)/T_(2)=(cosalpha)/(cosbeta)

If O is at equilibrium then the values of the tension T_(1) and T_(2) are, ( 20 N is acting vertically downwards at O ).

An ideal gas passes from one equllibrium state (P_(1) ,V_(1), T_(1), N) to anoter equilibrium state (2P_(1) , 3V_(1), T_(2), N) Then