[" The combined resistance "R" of two resistors "R_(1)&R_(2)(R_(1),R_(2)>0)" is given by,"(1)/(R)=(1)/(R_(1))+(1)/(R_(2))],[R_(1)+R_(2)=" constant.Prove that the maximum resistance Ris obtained by choosing "R_(1)=R_(2)]

The conbined resistance R of two resistors R,& R_(2)(R_(1),R_(2) gt 0) is given by . (1)/(R)=(1)/(R_(1)) +(1)/(R_(2)). If R_(1)+R_(2)= constant Prove that the maximum resistance R is obtained by choosing R_(1)=R_(2)

The combined resistance R of two resistors R_(1) and R_(2) " where " R_(1), R_(2) gt 0 is given by (1)/(R) = (1)/(R_(1)) + (1)/(R_(2)) If R_(1) + R_(2) = C (constant), show that the maximum reistance R is obtained by chossing R_(1) = R_(2)

The combined resistance R of two resistors R_1 and R_2(R_1,R_2>0) is given by 1/R=1/R_1+1/R_2 . If R_1+R_2=C (a constant), show that the maximum resistance R is obtained by choosing R_1=R_2 .

The combined resistance R of two resistance R_1 and R_2 , where R_1, R_2 ge 0 is given by (1/R) = (1/R_1) + (1/R_2) . If R_1 + R_2 =c (where c is constant), show that the maximum resistance R is obtained by choosing R_1 = R_2

The combined resistance of two resistors R_1 and R_@ (R_1,R_2>0) is given by 1/R= 1/R_1 + 1/R_2 . If R_1 + R_2 =C (a constant), show that maximum resistance R is obtained by choosing R_1 = R_2

The combined resistance of two resistors R_(1) and R_(1)" is given by "1/R=1/R_(1)+1/R_(2)," where "R_(1)+R_(2) = C (constant ), show that R is maximum when R_(1)= R_(2) .

The equivalent resistance (R_s) of a series combination of resistors is given by 1/R_s = 1/R_1 + 1/R_2 + …………. .

(1)/(r^(2))+(1)/(r_(1)^(2))+(1)/(r_(2)^(2))+(1)/(r_(3)^(2)) equals