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[" A bar of iron is "10cm" at "20^(0)C" .At "],[19^(0)C" it will be "(alpha" of iron "=11times10^(-6)],[/^(0)C)],[" 11"times10^(-6)cmlonger],[" 11"times10^(-6)cmshorter],[" 11"times10^(-5)cmshorter],[" 11"times10^(-5)cmlonger]

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A bar of iron is 10 cm at 20^(@)C . At 19^(@)C it will be ( alpha of iron =11xx10^-6//^(@)C )

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Solve: 11.2times0.10

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An iron bar 10 cm in length is kept at 20^@C . If the coefficient of linear expansion of iron is alpha = 11 xx 10^(-6).^(@)C^(-1) , then at 19^(@)C it will be

An iron bar 10 cm in length is kept at 20^@C . If the coefficient of linear expansion of iron is alpha = 11 xx 10^(-6).^(@)C^(-1) , then at 19^(@)C it will be