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Basic strength of CH-=overset(Theta)C(l)...

Basic strength of `CH-=overset(Theta)C(l), CH_(2)=overset(Theta) CH(II) and CH_(3)overset(Theta)CH_(2)(III)` will be in order

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Arrange the following in correct order of their stability ? (I) CH-=overset(Theta)C " "(II) CH_(2)=overset(Theta)CH " "(III) CH_(3)-overset(Theta)CH_(2)

Which one of the following is most stable? : CH -= overset(.. Theta)C , CH_2 = overset(..)CH^(Theta) , CH_3 - overset(..)CH_2^(Theta) , CH_3 - O^( Theta)

Write stability order of following intermediates: (a)HC -= overset(Theta)C" "(b) CH_(3) - overset(Theta)CH - CH_(3) (c) CH_(3) - C underset(CH_(3))underset(|)overset(CH_(3))overset(|)Theta

CH_(3)overset(Theta)(C)H-CO-CH_(3)(I),CH_(3)CH_(2)-CO-overset(Theta)(C)H_(2)(II)andoverset(Theta)(C)H_(2)CH_(2)-CO-CH_(3)(III) , The correct order of stability of these carbanious is-

Arrange the following anions in increasing order of stability and give reasons: CH_(2)=overset(Theta)(C)H,CH_(3)overset(Theta)(C)H_(2),CH-=overset(Theta)(C)

Decreasing order of stability of the given carbanions is (a) CH_3-C-=overset(Theta)C: (b) H-C-=overset(Theta)C: (c )CH_3-overset(Theta)overset(..)CH_2

The increasing order of basicity for the following intermediates is (from weak to strong) H_(3)C-underset("(i)")underset(CH_(3))underset("| ")overset(CH_(3))overset("| ")(C^(Theta))" "underset("(ii)")(H_(2)C=CH-overset(Theta)CH_(2))" "underset("(iii)")(HC=overset(Theta)C)" "underset("(iv)")(overset(Theta)CH_(3))" "underset("(v)")(overset(Theta)CN)