Two galvanometers A and B require 3 mA and 5 mA respectively to produce the same deflection of `i_(0)` division. Then

Two galvanometers A and B require 3 mA and 6 mA respectively, to produce the same deflection of 10 divisions. Then,

Two galvanometers A and B require 3 mA and 6 mA respectively, to produce the same deflection of 10 divisions. Then,

Two galvanometers A and B require 3mA and 5mA respectively to produce the same deflection of 10 division then

Two galvanometer A and B require the current of 4 mA and 7mA repectively to produce the same deflection of 20 divisions. Then

When 3 mA and 5 mA currents are passed through two galvanometers P and Q, they give same deflection of 10 divisions. Hence

A galvanometer coil has a resistance of 10A and the meter shows full scale deflection for a current of 1mA. The shunt resistance required to convert the galvanometer into an ammeter of range 0-100mA is about

A moving coil galvanometer shows a deflection of 50^@ for a current of 0.3 mA. What current will produce a deflection of 40^@ ?