A proton is to circulate the earth along the equator with a speed of `1*0xx10^7ms^-1`. Find the minimum magnetic field which should be created at the equator for this purpose. The mass of proton `=1*7xx10^(-27)kg` and radius of earth `=6*37xx10^6m`.

A proton is to circulate the earth along the equator with a speed of 1.0 xx 10^(7) m/s. The minimum magnetic field which should be created at the equator for this purpose. (The mass of proton =1.7 xx 10^(-27) kg and radius of earth = 6.37 xx 10^(6) m.) will be (in "Wb/m"^(2) )

A proton is projected with a velocity of 3xx10^(6) m//s perpendicular to a uniform magnetic field of 0.6 T .Find the acceleration of the proton.mass of proton =5/3xx10^(-27) kg

A proton enters a magnetic field of flux density 2*5T with a speed of 1*5xx10^7ms^-1 at an angle of 30^@ with the field, Find the force on the proton.

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

A proton is projected with a velocity 10^(7)ms^(-1) , at right angles to a uniform magnetic field of induction 100mT . The time ( in second ) taken by the proton to traverse 90^(@) are is : ( Mass of proton =1.65xx10^(-27)kg an charge of proton =1.6 xx10^(-19)C)

The electron in the hydrogen atom circles around the proton with a speed of 2.18 xx 10^(6)ms^(-1) in an orbit of radius 5.3 xx 10^(-11)m . What magnetic field does it produce at the proton ?