समीकरण `9x^(2) - 16y^(2) + 18x + 32y - 151 = 0`
नाभियो के निर्देशांक होंगे

Show that the equation 9x^(2) - 16y^(2) - 18x - 64y - 199 = 0 represents the equation of a hyperbola, find the coordinates of its centre and foci and also the equations of its directrices

Find the centre, eccentrcity, foci and directrices of the hyperboal : 9x^(2) - 16y^(2) + 18x + 32y - 151 = 0 .

The foci of the hyperbola 9x^(2) -16y ^(2)+18x +32 y- 151=0 are

Find the foci of the hyperbola 9x^(2) - 16y^(2) + 72 x - 32 y - 16 = 0

The length of the conjugate axis of the hyperbola 9x^(2) -16y^(2) - 18x -64y + 89 =0 is a) 8 b) 6 c) 4 d) 5

The length of the transverse axis of the hyperbola 9x^(2) - 16y^(2) -18x -32y - 151 =0 is

the centre of the hyperbola 9x^(2 )- 16y^(2)+ 72 x - 32y -16=0 is

The eccentricity of the ellipse 9x^(2) + 5y^(2) - 18x - 2y - 16 = 0 is