समीकरण `9x^(2) - 16y^(2) + 18x + 32y - 151 = 0`
नाभिलम्ब की लम्बाई

Find the centre, eccentrcity, foci and directrices of the hyperboal : 9x^(2) - 16y^(2) + 18x + 32y - 151 = 0 .

The length of the transverse axis of the hyperbola 9x^(2) - 16y^(2) -18x -32y - 151 =0 is

The length of the transverse axis of the hyperbola 9x^(2)-16y^(2)-18x -32y - 151 = 0 is

The length of the transverse axis of the hyperbola 9x^(2)-16y^(2)-18x -32y - 151 = 0 is

The length of the transverse axis of the hyperbola 9x^(2)-16y^(2)-18x -32y - 151 = 0 is

The length of the transverse axis of the hyperbola 9x^(2)-16y^(2)-18x -32y - 151 = 0 is

The eccentricity of the ellipse 9x^(2) + 5y^(2) - 18x - 2y - 16 = 0 is

The latus rectum of a hyperbola 9x^(2) - 16y^(2) + 72x-32y-16 = 0 is :

Show that the equation 9x^(2) - 16y^(2) - 18x - 64y - 199 = 0 represents the equation of a hyperbola, find the coordinates of its centre and foci and also the equations of its directrices

Find the foci of the hyperbola 9x^(2) - 16y^(2) + 72 x - 32 y - 16 = 0