(a) Find the energy needed to remove a neutron from the nucleus of the calcium isotope `._(20)^(42)Ca`.
(b) Find the energy needed to remove a proton from this nucleus.
(c ) Why are these energies different? Mass of .`_(20)^(40)Ca =40.962278u`, mass of proton ` =1.007825 u`.

(a) Find the energy needed to remove a neutron from the nucleus of the calcium isotopes ._(20)^(42)Ca (b) Find the energy needed to remove a proton from this nucleus (c ) Why are these energies different ? Atomic masses of ._(20)^(41)Ca and ._(20)^(42)Ca are 40.962278 u and 41.958622 u respectively.

The wavelength of photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly .

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1MeV energy is nearly

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1MeV energy is nearly

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1MeV energy is nearly

The wavelength of a photon needed to remove a proton from a nucleus. which is bound to the nucleus with 1 MeV energy is nearly

The wavelength of a photon needed to remove a proton from a nucleus which is bound to the nucleus with 1 MeV energy is nearly.

Consider the following reaction: ""_(20)Ca^(42) to ""_(20)Ca^(41) + ""_(0)n^(1) Calculate the energy E required to remove this neutron from ""_(20)Ca^(42) . Further, energy required to remove a proton from ""_(20)Ca^(42) is E' What would you suggest whether E' would be less than or greater than E and why? Mass of ""_(20)Ca^(42) = 41.9586 Mass of ""_(20)Ca^(41) = 40.9622 u Mass of neutron =1.0072 u