Find `^^_(m)^(oo) ("in" Omega^(-1) cm^(2) mol^(-1))` for strong electroyte `AB_(2)` in water at `25^(@)` form the following data.
`|{:("Conc".C("mole"//L),0.25,1),(^^_(m)(W^(1-)cm^(2)//mol),160,150):}|`

Calculate the value of Lambda_(m) ^prop for SrCl_(2) in water at 25^(@)C from the following data : {:(Conc. (mol//l t),,0.25,,1),(Lambda_(m)(Omega^(-1)cm^(2)mol^(-1)),,260,,250):}

Calculate the value of Lambda_(m) ^prop for SrCl_(2) in water at 25^(@)C from the following data : {:(Conc. (mol//l t),,0.25,,1),(Lambda_(m)(Omega^(-1)cm^(2)mol^(-1)),,260,,250):}

Calculate the value of Lambda_(m) ^prop for SrCl_(2) in water at 25^(@)C from the following data : {:(Conc. (mol//l t),,0.5,,1),(Lambda_(m)(Omega^(-1)cm^(2)mol^(-1)),,260,,250):}

From the following molar conductivities at infinite dilution. Lambda_(m)^(@) for Ba(OH)_(2) = 457.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for BaCl_(2) = 240.6 Omega^(-1) cm^(2) "mol"^(-1) Lambda_(m)^(@) for NH_(4) Cl = 129.8 Omega^(-1) cm^(2) "mol"^(-1) Calculate Lambda_(m)^(@) for NH_(4) OH .

The following data is obtained at 25^(@)C , for an aqueous solution of NaCl {:("Conc.(in molarity)",0.25,0.64),(A_(m)("in" ohm^(-1)m^(2)"mol"^(-1)),0.025,0.019):} At 25^(@)C , the molar conductivity of 0.49M aqueous NaCl solution is:

The Lambda_(m)^(@) values for NaCl and KCl are 126.5 and 149.9 Omega^(-1) cm^(2) "mol"^(-1) respectively. The ionic conductance of Na^(+) at infinite dilution is 50.1 Omega^(-1) cm^(2) "mol"^(-1) . Calculate the ionic conductance at infinite dilution for potassium ion ( K^(+)) .

Given the following molar conductivities are 25^(@) C , HCl , 426 Omega^(-1) cm^(2) mol^(-1) , NaCl , 126 Omega^(-1)cm^(2) mol^(-1) , NaC( sodium crotonate ) , 83 Omega^(-1) cm^(2) mol^(-1) , what is the ionization constant of crotonic acid ? If the conductivity of a 0.001 M corotonic acid solution is 3.83 xx 10^(-5) Omega^(-1) cm^(-1) ?

The molar conductivity of weak monobasic acid (HA) at infinite dilution is 50xx10^(-2)Omega^(-1) cm^(-2)"mol"^(-1) . The pH of 0.02M weak monobasic acid (HA) solution, whose molar conductivity is 25xx10^(-2)Omega^(-1) cm^(-2)"mol"^(-1) is:

0.1 "mole" AgNO_(3) is added in 250 mL of saturated solution of AgCl at 25^(@)C without changing volume. Given: K_(sp) of AgCl=1.0xx10^(-10)M^(2) Ionic conductance of Ag^(+)"ion"=60Omega^(-1)cm^(2) "mol"^(-1) Ionic conductance of Cl^(-) ion = 75Omega^(-1)cm^(2) "mol"^(-1) Ionic conductance of NO_(3)^(-) "ion"=75 Omega^(-1) [Cl^(-)] in the final solution is equal to :