The kinetic energy of `4 mol` of nitrogen gas at `127^(@) C` is …….. `cal(R = 2 cal mol^(-1) K^(-1))`

The kinetic enerrgy of 4 mole sof nitrogen gas at 127^(@)C is (R=2" cal "mol^(-1)K^(-1))

The total kinetic energy of 2 mol of an ideal gas at 127^(@)C is ( Use R = 8.3 JK^(-1) mol^(-1) )

Find the kinetic energy of 1 g of nitrogen gas at 77^(@)C . Given R=8.31" J "mol^(-1)K^(-1)

Find the kinetic energy of 1 g of nitrogen gas at 77^(@)C . Given R=8.31" J "mol^(-1)K^(-1)

The kinetic energy for 14 g of nitrogen gas at 127^(@)C is nearly (mol. Mass of nitrogen = 28 and gas constant = 8.31 J/mol K)

The kinetic energy for 14 g of nitrogen gas at 127^(@)C is nearly (mol. Mass of nitrogen = 28 and gas constant = 8.31 J/mol K)