The integer just above`(sqrt(3)+1)^(2n)` is, for all `n in N.`

Let N be the integer next above (sqrt3+1)^(2018) . The greatest integer ‘p’ such that (16)^(p) divides N is equal to:

Let N be the integer next above (sqrt3+1)^(2018) . The greatest integer ‘p’ such that (16)^(p) divides N is equal to:

Integer just greater then (sqrt(3)+1)^(2n) is necessarily divisible by

Integer just greater tehn (sqrt(3)+1)^(2n) is necessarily divisible by (A) n+2 (B) 2^(n+3) (C) 2^n (D) 2^(n+1)

Integer just greater tehn (sqrt(3)+1)^(2n) is necessarily divisible by (A) n+2 (B) 2^(n+3) (C) 2^n (D) 2^(n+1)

The greatest positive integer which divides n(n+1)(n+2)(n+3) for all n in N is 1.2 2.6 3.24 4.120

Prove by induction that the integer next greater than (3+sqrt(5))^n is divisible by 2^n for all n in N .

Prove by induction that the integer next greater than (3+sqrt(5))^n is divisible by 2^n for all n in N .