`3log_2 5+log_2 10-log_2 625`

Find the value of 2log2/5 +3 log25/8 -log 625/128

Find the value of 2log2/5 +3 log25/8 -log 625/128

log_10(log_2 3) + log_10(log_3 4) + log_10(log_4 5) + ........ + log_10 (log_1023 1024) simplifies to

A denotes the product xyz where x,y and z satisfy log_3 x= log5-log7 and log_5 y=log7-log 3 and log_7 z=log 3-log5 B denotes the sum of square of solution of the equation, log_2(log_2 x^6 - 3) - log_2(log_2 x^4 - 5) = log_2 3 C denotes characterstio of logarithm log_2 (log_2 3)-log_2 (log_4 3)+log_2(log_4 5)-log_2(log_6 5)+log_2 (log_6 7)-log_2 (log_6 3) The valuo of A+B+C is equal to

Prove that log_5 log_2 log_3 log_2 512=0

Prove that log_(2) [log_(4) {log_(5) (625)^(4)}]=1

Simplify: 3log_(3)5 + log_(3)10 - log_(3)625 .

Let x=(anti log_2 3)*log_3 2, y=log_2(log_3 512))"and"z=log_5 3*log_7 5*log_2 7, then xyz is equal to

If 3(log 5 - log 3) - (log 5 - 2 log 6) = 2 - log x, find x.

If log_2 (log_2 (log_3 x)) = log_2 (log_3 (log_2 y))=0 , then the value of (x+y) is