[f(x)=int_(2)^(x)(2t-5)dt],[" unction "]" at the points where the graph "c

The angle between the tangent lines to the graph of the function f(x)=int_(2)^(x)(2t-5)dt at the points where the graph cuts the x-axis is

If f(x)=int_(0)^(x)tf(t)dt+2, then

If f(x)=int_(2)^(x)(dt)/(1+t^(4)) , then

If f(x)=int_(2)^(x)(dt)/(1+t^(4)) , then

If f(x)=int_(2)^(x)(dt)/(1+t^(4)) , then

Let f(x) = int_(-2)^(x)|t + 1|dt , then

Let f(x) = int_(-2)^(x)|t + 1|dt , then

If f(x)=int_(0)^(x)|t-1|dt , where 0lexle2 , then

If f(x)=int_(0)^(x)|t-1|dt , where 0lexle2 , then

If f(x)=int_(0)^(x)|t-1|dt , where 0lexle2 , then