`PQ_(2)` dissociates as
`PQ_2 (g)hArrPQ(g)+Q(g)`
The initial pressure of `PQ_2` is 600 mm Hg. At equilibrium, the total pressure is 800mm Hg. Calculate the value of `K_p`.

XY_(2) dissociates XY_(2)(g) hArr XY(g)+Y(g) . When the initial pressure of XY_(2) is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

XY_(2) dissociates XY_(2)(g) hArr XY(g)+Y(g) . When the initial pressure of XY_(2) is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

XY_(2) dissociates XY_(2)(g) hArr XY(g)+Y(g) . When the initial pressure of XY_(2) is 600 mm Hg, the total equilibrium pressure is 800 mm Hg. Calculate K for the reaction Assuming that the volume of the system remains unchanged.

AB_(2) dissociates as : AB_(2 (g)) hArr AB_((g)) + B_((g)) When the intial pressure of AB_(2) is 500 mm Hg , the total equilibrium pressure is 700 mm Hg . Calculate equilibrium constant for the reaction , assuming that the volume of the system remains unchanged .

AB_(2(g)) dissociates as AB_(2(g)) harr AB_(2(g))+B_((g)) . The initial pressure of AB_2 is 600 mm Hg and equilibrium pressure of the mixture of gases is 800 mm Hg. Then