In order to make the weight of a 5kg body to zero at the equator. The angular speed of the earth would must be (take, `g = 10m//s^(2)` and radius of the earh, `R = 6400 km)`

Suppose the earth increases it speed of rotation. At what new time period will the weight of a body on the equator becomes zero ? (Take, g = 10 ms^(-2) and radius of earth R = 6400 km)

Suppose the earth increases it speed of rotation. At what new time period will the weight of a body on the equator becomes zero ? (Take, g = 10 ms^(-2) and radius of earth R = 6400 km)

What would be the angular speed of earth, so that body lying on equator may appear weightless? ( g = 10 m//s^2 , radius of earth = 6400 km)

What would be the angular speed of earth, so that bodies lying on equator may experience weightlessness ? ( g = 10m//s^(2) and radius of earth = 6400 km)

If the angular velocity of earth's spin is increased such that the bodies at the equator start floating, the duration of the day would be approximately: ["Take " g=10ms^(-2), " the radius of the earth "R =6400 xx 10^(3)m, " Take "pi=3.14]

Suppose the earth increases its speed of rotation . At what new time period will the weightof a body on the equator becomes zero? Take g=10 m/s^2 and radius of the earth R=6400 km .

Suppose the earth increases its speed of rotation . At what new time period will the weightof a body on the equator becomes zero? Take g=10 m/s^2 and radius of the earth R=6400 km .

If g on the surface of the earth is 9.8m//s^(2) , its value at a height of 6400 km is (Radius of the earth =6400 km)