" iii) "quad sim(p vv q)vv(sim p^^q)-=sim p

The Boolean expression sim(p vv q)vv(sim p^^q) is equivalent to (1)-p(2)p(3)q(4)sim q

The incorrect statement is p rarr q is logically equivalent to -p vv q. If the truth-values of p,qr are T,F,T respectively,then the truth value of (p vv q)^^(q vv r) is T .sim(p vv q vv r)-=sim p^^sim q^^sim r The truth value of p^^sim(p^^q) is always T.

(p ^^ q) vv (~q ^^ p) -=

(p ^^ q) vv (~q ^^ p) -=

let (i) (p vv q)^^(p vv sim q),(ii)(p^^q)^^(q vv sim q),(iii).(p vv q)^^(p vv sim q),(iv)(p vv q)vv(p^^sim q) then which one is tautology

p vv ~(p ^^ q) is a

(p^^~q)vv(~p^^q) is :

((p^^q)vv(p vv sim q))^^(sim p^^sim q) is equivalent to (A)sim p^^sim q(B)p^^sim q(C)p vv sim q(D)sim p vv q

The statement sim(sim p rarr q) is equivalent to (A)p vv sim q(B)sim p^^q(C)sim p^^sim q(D)sim p vv q