tan theta_(1)=K cot theta_(2)th_(2n)(cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=

If Tan theta_(1)=k cot theta_(2) then (cos (theta_(1)+theta_(2)))/(cos (theta_(1)-theta_(2)))=

if tan theta_(1)=k cot theta_(2) then find (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=

If tan theta_(1)tan theta_(2)=k, then (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))=(1+k)/(1-k) b.(1-k)/(1+k) c.(k+1)/(k-1) d.(k-1)/(k+1)

If tan theta_(1).tantheta_(2)=k , then: (cos(theta_(1)-theta_(2))/(cos(theta_(1)+theta_(2)))=

If tan theta_1= k cot theta_2 " then " (cos (theta_1- theta_2))/(cos(theta_1+theta_2))=

If cos theta_(1)=2cos theta_(2), then tan((theta_(1)-theta_(2))/(2))tan((theta_(1)+theta_(2))/(2)) is equal to (a) (1)/(3)(b)-(1)/(3)(c)1(d)-1

(cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0then(tan theta_(1)*tan theta_(2))/(cot theta_(2)*cot theta_(4))

If (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0, then tantheta_(1)tan theta_(2)tan theta_(3)tan theta_(4)=

If (cos(theta_(1)-theta_(2)))/(cos(theta_(1)+theta_(2)))+(cos(theta_(3)+theta_(4)))/(cos(theta_(3)-theta_(4)))=0, then tantheta_(1)tan theta_(2)tan theta_(3)tan theta_(4)=