" If "(a)/(cos A)=(b)/(cos B)=(c)/(cos C)," then "Delta ABC" is "

In a Delta ABC with usual notations, if (a)/(cos A)=(b)/(cos B)=(c )/(cos C) , then the triangle is :

If (a)/( cos A) = (b)/( cos B) = (c ) /( cos C) , then show that Delta ABC is equilateral.

In a triangle ABC if (cos A)/a=(cos B)/b= (cos C)/c , then Delta ABC is

In Delta ABC,(a)/(cos A)=(b)/(cos B)=(c)/(cos c); If b=2 'then the area of the triangle is

In Delta ABC , (a)/( cos A) = (b) /( cos B ) = ( c ) /( cos C ) , If b= 2 then the area of the triangle is

If in a Delta ABC,(cos A)/(a)=(cos B)/(b)=(cos C)/(c), then find the measures of angles A,B,C.

In a triangle ABC,if (cos A)/(a)=(cos B)/(b)=(cos C)/(c) and the side a=2 then area of triangle is and the side a=2

In a triangle ABC, if (cos A)/(a) =(cos B)/(b ) =(cos C)/(c) and the side a=2, then the area of the triangle is-