Home
Class 11
PHYSICS
The escape velocity corresponding to a p...

The escape velocity corresponding to a planet of mass `M` and radius `R` is `50 km s^(-1)`. If the planet's mass and radius were `4M` and `R`, respectively, then the corresponding escape velocity would be

Promotional Banner

Similar Questions

Explore conceptually related problems

The escape velocity form the centre of a unifrom ring of mass M and radius R is :

The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator is

The angular velocity of rotation of a planet of mass M and radius R, at which the matter start to escape from its equator is

The escape velocity on the surface of the earth is 11.2 kms^(-1) . If mass and radius of a planet is 4 and 2 tims respectively than that of the earth, what is the escape velocity from the planet?

Determine the escape velocity of a planet with mass 3xx10^(25)"kg and radius" 9xx10^(6)m.

Determine the escape velocity of a planet with mass 3xx10^(25)"kg and radius" 9xx10^(6)m.

The escape velocity of the earth is 11.2 km/s. For a planet whose mass and radius are twice those of the earth, the escape velocity will be

The escape velocity on the surface of the earth is 11.2 km/s. If mass and radius of a planet is 4 and 2 times respectively than that of earth, what is the escape velocity from the planet ?