[" In "a Delta ABC," If "C" is a right a...

[" In "a Delta ABC," If "C" is a right angle then "Tan^(-1)((a)/(b+c))+Tan^(-1)((b)/(c+a))=],[" 1) "(pi)/(3)quad " 2) "(pi)/(4)," 3) "(pi)/(6)quad " 4) "(5 pi)/(2)]

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In a ABC, if C is a right angle,then tan^(-1)((a)/(b+c))+tan^(-1)((b)/(c+a))=(pi)/(3)(b)(pi)/(4)( c) (5 pi)/(2)( d) (pi)/(6)

In a triangle A B C , , if C is a right angle, then tan^(-1)(a/(b+c))+tan^(-1)(b/(c+a))= (a) pi/3 (b) pi/4 (c) (5pi)/2 (d) pi/6

If angle A = 90 ^(@) in the triangle ABC, then tan ^(-1) (( c )/(a+b)) + tan ^(-1) ((b)/(a+c)) is equal to : a)0 b)1 c) (pi)/(4) d) (pi )/(6)

If C is a right angle in the triangle ABC, show that, tan^(-1) 'a/(b+c)' + tan^(-1) 'b/(c+a)' = pi/4 .

tan^(-1)((x)/(y))-tan^(-1)((x-y)/(x+y)) is (A) (pi)/(2)(B)(pi)/(3)(C)(pi)/(4)(D)(pi)/(4) or 3(pi)/(4) is (A) (pi)/(2)(B)

The value of tan^(-1) (2) + tan^(-1) (3) is equal to a) (3pi)/(4) b) (pi)/(4) c) (pi)/(3) d) tan^(-1) (6)

If in triangle ABC, C = 90^circ then prove that tan^(-1) (a/(c+b)) + tan^(-1) (b/(a+c)) = pi/4 .

tan^(-1)(x/y)-tan^(-1)((x-y)/(x+y)) is (A) pi/2 (B) pi/3 (C) pi/4 (D) pi/4 or (3pi)/4