For the equlibrium `SO_(3)(g)hArrSO_(2)(g)+1/2O(2)(g)` the molar mass at equlibrium was observed to be 60. then the degree of dissociation of `SO_(3)` would be

At 627^(@)C and 1 atm SO_(3) is partially dissociated into SO_(2) and O_(2) by the reaction SO_(3)(g)hArrSO_(2)(g)+1//2O_(2)(g) The density of the equilibrium mixture is 0.925 g L^(-1) . What is the degree of dissociation?

At 627^(@)C and 1 atm SO_(3) is partially dissociated into SO_(2) and O_(2) by the reaction SO_(3)(g)hArrSO_(2)(g)+1//2O_(2)(g) The density of the equilibrium mixture is 0.925 g L^(-1) . What is the degree of dissociation?

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

At 627^(@) C and one atmosphere SO_(3) is is partially dissociated into SO_(2) and O_(2) by SO_(3(g)) hArr SO_(2(g)) + (1)/(2) O_(2(g)). The density of the equilibrium mixture is 0.925 g/litre. What is the degree of dissociation ?

At 727^(@)C and 1.2 atm of total equilibrium pressure, SO_(3) is partially dissociated into SO_(2) and O_(2) as: SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) The density of equilibrium mixture is 0.9 g//L . The degree of dissociation is:, [Use R=0.08 atm L mol^(-1) K^(-1)]

At 727^(@)C and 1.2 atm of total equilibrium pressure, SO_(3) is partially dissociated into SO_(2) and O_(2) as: SO_(3)(g)hArrSO_(2)(g)+(1)/(2)O_(2)(g) The density of equilibrium mixture is 0.9 g//L . The degree of dissociation is:, [Use R=0.08 atm L mol^(-1) K^(-1)]