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sin^(8)theta-cos^(8)theta=(sin^(2)theta-...

sin^(8)theta-cos^(8)theta=(sin^(2)theta-cos^(2)theta)

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The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

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(sin^(8)theta-cos^(8)theta)/(cos2theta(1+cos^(2)2theta))=?

The range of the function f(theta)=sqrt(8sin^(2)theta+4cos^(2)theta-8sin theta cos theta) is

(2sin theta*cos theta-cos theta)/(1-sin theta+sin^(2)theta-cos^(2)theta)=cot theta

Prove : (2 sin theta cos theta-cos theta)/(1-sin theta+sin^(2) theta-cos^(2) theta)=cot theta