Home
Class 11
MATHS
If H is orthocentre of acute angled tria...

If H is orthocentre of acute angled triangle ABC, then image of H with respect to side AB always lies on (1) Circumcircle of `triangleABC` (2) Circumcircle of `triangleAHB` (3) Escribed circle opposite to vertex C (4) Circumcircle of `triangleAIB` where `I` is incentve `triangleABC`

Text Solution

Verified by Experts

`/_HCF=A+C-90^0`
`/_CHF=180-(A+C)=/_B`
`/_A+/_B+/_C=180`
`In/_ABD` and`/_AID`
HD=ID
`/_ADB=/_ADI`
AD=AD
`/_ABD cong /_AID`
...
Promotional Banner

Similar Questions

Explore conceptually related problems

If H is the orthocentre of a acute-angled triangle ABC whose circumcircle is x^(2)+y^(2)=16 then circum diameter of the triangle HBC is

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^2+y^2=16 , then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^2+y^2=16 , then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^2+y^2=16 , then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^2+y^2=16 , then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^2+y^2=16 , then circumdiameter of the triangle HBC is (a)1 (b) 2 (c) 4 (d) 8

If H is the othrocenter of an acute angled triangle ABC whose circumcircle is x^(2)+y^(2)=16, then circumdiameter of the triangle HBC is 1 (b) 2 (c) 4 (d) 8

Draw a triangle ABC, whose AB = 4.5 cm , BC = 3.5cm and angleABC = 90^@ . Now draw the circumcircle of triangleABC .

Let ABC be an acute angled triangle whose orthocentre is at H. If altitude from A is produced to meet the circumcircle of triangle ABC at D , then prove H D=4RcosBcosC

Let ABC be an acute angled triangle whose orthocentre is at H. If altitude from A is produced to meet the circumcircle of triangle ABC at D , then prove H D=4RcosBcosC