The radius of the earth is `6400 km` and `g=10m//sec^(2)`. In order that a dody of `5 kg` weight zero at the equator, the angular speed of the earth is

The radius of the Earth is 6400 km and g = 10 in order that a body of 5 kg weights zero at the equator, the angular speed of the Earth is ............ rad

The radius of the earth is 6400 km, the order of magnitude is

The radius of the earth is 6400 km, the order of magnitude is

What should be the angular speed of earth in radian/second so that a body of 5 kg weights zero at the equator? [Take g = 10 m//s^2 and radius of earth = 6400 km]

What should be the angular speed of earth in radian/second so that a body of 5 kg weights zero at the equator? [Take g = 10 m//s^2 and radius of earth = 6400 km]

If the value of g at the surface of the earth is 9.8 m//sec^(2) , then the value of g at a place 480 km above the surface of the earth will be (Radius of the earth is 6400 km)

If the value of g at the surface of the earth is 9.8 m//sec^(2) , then the value of g at a place 480 km above the surface of the earth will be (Radius of the earth is 6400 km)

With what speed should the earth rotate in order that the weight of a man on the equator is reduced to half his present weight , if the radius of the earth is 6400km.