`4I^(-)+Hg^(2+)rarrHgI_(4)^(2-)` , `1` mole each of `Hg^(2+)` and `I^(-)` will form….. Mole `HgI_(4)^(2-)`:

Objective question . i. A certains compound has the molecular formula X_(4) O_(6) . If 10 g of X_(4) O_(6) has 5.72 g X , then atomic mass of X is: a. 32 amu b. 42 amu c. 98 amu d. 37 amu ii. For 109% labelled oleum, if the number of moles of H_(2)SO_(4) and free SO_(3) be p and q , respectively, then what will be the value of (p - q)/(p + q) a. 1//9 b. 9 c. 18 d. 1//3 iii. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation, 2H_(2) O_(2) (aq) rarr 2 H_(2) O (l) + O_(2) (g) Under conditions where 1 mol gas occupies 24 dm^(3), 100 cm^(3) of X M solution of H_(2) O_(2) produces 3 dm^(3) of O_(2) . Thus, X is a. 2.5 b. 0.5 c. 0.25 d. 1 iv. 4 g of sulphur is burnt to form SO_(2) which is oxidised by Cl_(2) water. The solution is then treated with BaCl_(2) solution. The amount of BaSO_(4) precipitated is: a. 0.24 mol b. 0.5 mol c. 1 mol d. 0.125 mol v. A reaction occurs between 3 moles of H_(2) and 1.5 moles of O_(2) to give some amount of H_(2) O . The limiting reagent in this reaction is a. H_(2) and O_(2) both b. O_(2) c. H_(2) d. Neither of them vi. 4 I^(ɵ) + Hg^(2+) rarr HgO_(4)^(-) , 1 mole each of Hg^(2+) and I^(ɵ) will form: a. 1 mol of HgI_(4)^(2-) b. 0.5 mol of HgI_(4)^(-2) 0.25 mol of HgI_(4)^(2-) 2 mol of HgI_(4)^(-2)

Objective question . i. A certains compound has the molecular formula X_(4) O_(6) . If 10 g of X_(4) O_(6) has 5.72 g X , then atomic mass of X is: a. 32 amu b. 42 amu c. 98 amu d. 37 amu ii. For 109% labelled oleum, if the number of moles of H_(2)SO_(4) and free SO_(3) be p and q , respectively, then what will be the value of (p - q)/(p + q) a. 1//9 b. 9 c. 18 d. 1//3 iii. Hydrogen peroxide in aqueous solution decomposes on warming to give oxygen according to the equation, 2H_(2) O_(2) (aq) rarr 2 H_(2) O (l) + O_(2) (g) Under conditions where 1 mol gas occupies 24 dm^(3), 100 cm^(3) of X M solution of H_(2) O_(2) produces 3 dm^(3) of O_(2) . Thus, X is a. 2.5 b. 0.5 c. 0.25 d. 1 iv. 4 g of sulphur is burnt to form SO_(2) which is oxidised by Cl_(2) water. The solution is then treated with BaCl_(2) solution. The amount of BaSO_(4) precipitated is: a. 0.24 mol b. 0.5 mol c. 1 mol d. 0.125 mol v. A reaction occurs between 3 moles of H_(2) and 1.5 moles of O_(2) to give some amount of H_(2) O . The limiting reagent in this reaction is a. H_(2) and O_(2) both b. O_(2) c. H_(2) d. Neither of them vi. 4 I^(ɵ) + Hg^(2+) rarr HgO_(4)^(-) , 1 mole each of Hg^(2+) and I^(ɵ) will form: a. 1 mol of HgI_(4)^(2-) b. 0.5 mol of HgI_(4)^(-2) 0.25 mol of HgI_(4)^(2-) 2 mol of HgI_(4)^(-2)

HgCl_(2)+4KI to K_(2)[H_gI_(4)]+2KCl 1 mole each of Hg^(2+) and I^(-) will form how many moles of HgI_(4)^(2-)?

HgI_(2)darr+2HI to K_(2)[HgI_(4)]

HgI_(2)darr+2HI to K_(2)[HgI_(4)]

HgI_(2)darr+2HI to K_(2)[HgI_(4)]

HgI_(2)darr+KI hArrK_(2)[HgI_(4)]

HgI_(2)darr+KI hArrK_(2)[HgI_(4)]