One mole of a diatomic gas undergoes a process `P = P_(0)//[1 + (V//V_(0)^(3))]` where `P_(0)` and `V_(0)` are constant. The translational kinetic energy of the gas when `V = V_(0)` is given by

One mole of diatomic gas undergoes a process P=(P_0)/([1+(V//V_0)^3]) , where P_0 and V_0 are constants . The translational kinetic energy of the gas when V=V_0 is given by

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V)/(V_(0)))^(2)) where p_(0) and V_(0) are constants. Find temperature of the gas when V=V_(0) .

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V)/(V_(0)))^(2)) where p_(0) and V_(0) are constants. Find temperature of the gaas when V=V_(0) .

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V)/(V_(0)))^(2)) where p_(0) and V_(0) are constants. Find temperature of the gaas when V=V_(0) .

One mole of an ideal gas undergoes a process P = P_(0) [1 + ((2 V_(0))/(V))^(2)]^(-1) , where P_(0) V_(0) are constants. Change in temperature of the gas when volume is changed from V = V_(0) to V = 2 V_(0) is:

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V_(0))/(V))^(2)) . Here, p_(0) and V_(0) are constants. Change in temperature of the gas when volume is changed from V=V_(0) to V=2V_(0) is

One mole of an ideal gas undergoes a process p=(p_(0))/(1+((V_(0))/(V))^(2)) . Here, p_(0) and V_(0) are constants. Change in temperature of the gas when volume is changed from V=V_(0) to V=2V_(0) is