निम्नलिखित को सरल कीजिए -
`|{:(1,x,y),(0,cosx,siny),(0,sinx,cosy):}|`

cosx(1+cosy)dx-siny(1+sinx)dy=0

(cosx-cosy)^(2)+(sinx-siny)^(2)=?

prove that, |{:(1 ,cosx-sin x,cosx +sin x),(1,cos y-siny,cosy+sin y),(1,cosz-sinz ,cosz+sin z):}|=2|{:(1,cosx , sinx),(1,cosy,siny),(1,cosz,sinz):}|

(sinx-siny)/(cosx+cosy)=tan(x-y)/(2)

dy/dx=-(cosx(3cosy-7sinx-3))/(siny(3sinx-7cosy+7))

e^(x-y)(sinx+cosx)dx+(cosy-siny)dy=0