In the above question, if the internal resistance of the battery is 1 ohm , then what is the reading of ammeter

A resistance of 97 Omega is connected to a battery of emf 10 V . To measure the current passing in the circuit, an ammeter is inserted in series with the resistance. It is found that the ammeter reads 100 mA. What is the internal resistance of the battery if 2 Omega is the resistance of ammeter ?

The storage battery of a car has an EMF of 12 V . if the internal resistance of the battery is 0.4 ohms . What is the maximum current that can be drawn from the battery?

In Fig. 6.76, the ammeter (I) reads a current of 10 mA , while the voltmeter reads a potential difference of 3 V . The ammeters are identical, and the internal resistance of the battery is negligible (consider all ammeters and voltmers as nonideal). The resistance of ammeter is m xx 10^(2) Omega . What is the value of m ?

In Fig. 6.76, the ammeter (I) reads a current of 10 mA , while the voltmeter reads a potential difference of 3 V . The ammeters are identical, and the internal resistance of the battery is negligible (consider all ammeters and voltmers as nonideal). The resistance of ammeter is m xx 10^(2) Omega . What is the value of m ?

Two batteries A and B each of e.m.f. 2 V are connected in series to an external resistance R = 1 ohm . If the internal resistance of battery A is 1.9 ohms and that of B is 0.9 ohm , what is the potential difference between the terminals of battery A

Two batteries A and B each of e.m.f. 2 V are connected in series to an external resistance R = 1 ohm . If the internal resistance of battery A is 1.9 ohms and that of B is 0.9 ohm , what is the potential difference between the terminals of battery A

The emf (epsilon) and the internal resistance r of the battery shown in figure are 4.3V and 1.0 Ohm respectively.The external resistance R is 50 ohm .The resistances of the ammeter and voltmeter are 2.0 ohm and 200ohm respectively.(a)Find the reading of the two meters.

In the figure ammeter (i) reads a current of 10mA , while the voltmeter reads a potential difference of 3V . What does ammeter (ii) (in mA ) read? The ammeters are identical, the internal resistance of the battery is negligible. (Consider all ammeters and voltmeters as non ideal)

In the above question, the reading of ammeter is 40/x A . What is the value of x ?