If `Delta_1=|[2a,b,e],[2d,e,f],[4x,2y,2z]|,Delta_2=|[f,2d,e],[2z,4x,2y],[e,2a,b]|`, then the value of `Delta_1-Delta_2` is

If Delta_1 = |[1,1,1] , [x^2, y^2, z^2] , [x,y,z]| and Delta_2=|[1,1,1] , [yz, zx, xy] , [x,y,z]| then without expanding show that Delta_1= Delta_2

If Delta_1=|[a, b, c],[ x, y, z],[ p, q, r]| and Delta_2=|[q,-b, y],[-p, a,-x],[ r,-c, z]|, without expending or evaluating Delta_1 and Delta_2 , show that Delta_1+Delta_2=0

If Delta_1=|[a, b, c],[ x, y, z],[ p, q, r]| and Delta_2=|[q,-b, y],[-p, a,-x],[ r,-c, z]|, without expanding or evaluating Delta_1 and Delta_2 , show that Delta_1+Delta_2=0

If Delta_1=|[x, b, b],[ a, x, b],[ a, a, x]| a n d Delta_2=|[x, b],[ a, x]| are the given determinants, then Delta_1=3(Delta_2)^2 b. d/(dx)(Delta_1)=3Delta_2 c. d/(dx)(Delta_1)=3(Delta_2)^2 d. Delta_1=3(Delta_2)^ (3//2)

If Delta_1=|(1, 1 ,1),(a, b, c ),(a^2,b^2,c^2)|,Delta_2=|(1,b c, a),(1,c a, b),(1,a b, c)|,t h e n (a) Delta_1+Delta_2=0 (b) Delta_1+2Delta_2=0 (c) Delta_1=Delta_2 (d) none of these

If x^a y^b=e^m , x^c y^d=e^n ,Delta_1=|(m,b),(n,d)|,and Delta_2 =|(a,m),(c,n)| and Delta_3=|(a,b),(c,d)|, then the values of x and y are

If x^a y^b=e^m , x^c y^d=e^n ,Delta_1=|(m,b),(n,d)|,and Delta_2 =|(a,m),(c,n)| and Delta_3=|(a,b),(c,d)|, then the values of x and y are

If x^(2a)y^(3b)=e^(5m), x^(3c)y^(4d)=e^(2n), Delta_(1)=|(5m, 3b),(2n, 4d)|, Delta_(2)=|(2a, 5m),(3c, 2n)| and Delta_(3)=|(2a, 3b),(3c, 4d)| , then the values of x and y are