(a)/(b)=(7)/(3)

If (3a+7b)/(3a-7b)=(4)/(3) then find the value of the ratio (3a^(2)-7b^(2))/(3a^(2)+7b^(2))

If we reduce 3x+3y+7=0 to the form x cos alpha+y sin alpha=p, then the value of p is (7)/(2sqrt(3))( b) (7)/(3)( c) (3sqrt(7))/(2)( d) (7)/(3sqrt(2))

If alpha,beta are the zeros of the polynomial p(x)=4x^(2)+3x+7, then (1)/(alpha)+(1)/(beta) is equal to ( a )(7)/(3)(b)-(7)/(3)(c)(3)/(7)(d)-(3)/(7)

If 7x + 3y + 9 = 0 and y = kx + 7 are two parallel lines than k is (a)3/7 (b)-7/3 (c)3 (d)7

If alpha,\ beta are the zeros of the polynomial p(x)=4x^2+3x+7 , then 1/alpha+1/beta is equal to (a) 7/3 (b) -7/3 (c) 3/7 (d) -3/7

The value of 2a^(3)-[3a^(3)+4b^(3)-{2a^(3)+(-7a^(3))}5a^(3)-7b^(3)] is (a) -11a^(3)+3b^(3)( b) 7b^(3)+3a^(3)(c)11a^(3)-3b^(3) (d) (11a^(3)+3b^(3))

If P(A)=(2)/(7),P(B)=(3)/(7)" and "P(AuuB)=5/7 , then P (A/B) equals . . . . . . .

If alpha and beta are the roots of 4x^(2)=3x+7=0 then the value of (1)/(alpha)=(1)/(beta) is (4)/(7) b.-(3)/(7) c.(3)/(7)d-(3)/(4)

Expand : (7a + b)(7a-3b)

If (3a+7b)/(3a-7b)= 4/3 then find the value of the ratios (3a^2-7b^2)/(3a^2+7b^2)