" 19."2y^(2)-y+(1)/(8)

Factorise: 12(y^(2)+7y)^(2)-8(y^(2)+7y)(2y-1)-15(2y-1)^(2)

(1) / (2x) - (1) / (y) = - 1, (1) / (x) + (1) / (2y) = 8

Solve the following pairs of equations: (1)/(2x)-(1)/(y)=-1, (1)/(x)+(1)/(2y)= -8, x, y ne 0

From a point on x+2y-7=0 tangents are drawn to curve 13(x^(2)+y^(2)-2x+1)=(2x+3y-1)^(2) are perpendicular then the point is (a)(19,13) (b) (-19,13) (c) (19,-13) (d)(-19,-13)

I. x^(2)/2 + x - 1/2 = 1 II. 3y^(2) - 10y + 8 = y^(2) + 2y - 10

(i) Find the vector and cartesian equation of the line passing through the point (1,2,-4) and perpendicular to the two lines : (x - 8)/(3) = (y + 19)/(-16) = (z - 10)/(7) and (x - 15)/(3) = (y - 19)/(8) = (z - 5)/(-5) . (ii) Find the vector and cartesian equations of the line passing through the point (2,1,3) and perpendicular to the lines : (x -1)/(1) = (y -2)/(2) = (z - 3)/(3) and (x)/(-3) = (y)/(2) = (z)/(5) .

If (1)/(8)x+(1)/(8)y=y-2x , then what is the value of (x)/(y) ?

x ^ (2) + y ^ (2) + 1, x ^ (2) + 2y ^ (2) + 3, x ^ (2) + 3y ^ (2) + 4y ^ (2) + 2,2y ^ (2) + 6.3y ^ (2) + 8y ^ (2) + 1.2y ^ (2) + 3.3y ^ (2) +4] |

I. 4x^(2) - 20x+ 19 = 4x - 1 II. 2y^(2) = 26y+ 84