[*(24*(x)/(4)+(y)/(5)+1=23],[(x)/(5)+(y)/(4)=23]

((x+1)-(2x+4))/(3-5x)=(1)/(23)

Solve 3x - y = 23 and (x)/(3) + (y)/(4) = 4.

If x:y=1:1, then (3x+4y)/(5x+6y)=(7)/(11) (b) (17)/(11)(17)/(23)(d)(4)/(5)

If x : y=1:1,\ t h e n\ (3x+4y)/(5x+6y)= (a) 7/(11) (b) (17)/(11) (c) (17)/(23) (d) 4/5

If x : y=1:1,\ t h e n\ (3x+4y)/(5x+6y)= (a) 7/(11) (b) (17)/(11) (c) (17)/(23) (d) 4/5

{:((4)/(x) + 3y = 14),((3)/(x) - 4y = 23):}

The locus of a point "P" ,if the join of the points (2,3) and (-1,5) subtends right angle at "P" is x^(2)+y^(2)-x-8y+13=0 x^(2)-y^(2)-x+8y+3=0 x^(2)+y^(2)-4x-4y=0,(x,y)!=(0,4)&(4,0) x^(2)+y^(2)-x-8y+13=0,(x,y)!=(2,3)&(-1,5)

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .

By solving equations 3x + 4y = 23 and 5x + 12y = 39 with the help of cross multiplication method, we obtain (x)/(a) = (y)/(b) = (1)/(c ) , then find (a + 4b)/(5c) .